5u^2+26u-24=6u-25

Solution for 5u^2+26u-24=6u-25 equation:

5u^2+26u-24=6u-25

We move all terms to the left:

5u^2+26u-24-(6u-25)=0

We get rid of parentheses

5u^2+26u-6u+25-24=0

We add all the numbers together, and all the variables

5u^2+20u+1=0

a = 5; b = 20; c = +1;
Δ = b2-4ac
Δ = 202-4·5·1
Δ = 380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{380}=\sqrt{4*95}=\sqrt{4}*\sqrt{95}=2\sqrt{95}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-2\sqrt{95}}{2*5}=\frac{-20-2\sqrt{95}}{10}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+2\sqrt{95}}{2*5}=\frac{-20+2\sqrt{95}}{10}
$